3.7.2 \(\int \frac {x^{5/2}}{(a-b x)^{5/2}} \, dx\) [602]

Optimal. Leaf size=95 \[ \frac {2 x^{5/2}}{3 b (a-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a-b x}}-\frac {5 \sqrt {x} \sqrt {a-b x}}{b^3}+\frac {5 a \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a-b x}}\right )}{b^{7/2}} \]

[Out]

2/3*x^(5/2)/b/(-b*x+a)^(3/2)+5*a*arctan(b^(1/2)*x^(1/2)/(-b*x+a)^(1/2))/b^(7/2)-10/3*x^(3/2)/b^2/(-b*x+a)^(1/2
)-5*x^(1/2)*(-b*x+a)^(1/2)/b^3

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Rubi [A]
time = 0.02, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.312, Rules used = {49, 52, 65, 223, 209} \begin {gather*} \frac {5 a \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a-b x}}\right )}{b^{7/2}}-\frac {5 \sqrt {x} \sqrt {a-b x}}{b^3}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a-b x}}+\frac {2 x^{5/2}}{3 b (a-b x)^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^(5/2)/(a - b*x)^(5/2),x]

[Out]

(2*x^(5/2))/(3*b*(a - b*x)^(3/2)) - (10*x^(3/2))/(3*b^2*Sqrt[a - b*x]) - (5*Sqrt[x]*Sqrt[a - b*x])/b^3 + (5*a*
ArcTan[(Sqrt[b]*Sqrt[x])/Sqrt[a - b*x]])/b^(7/2)

Rule 49

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + 1))), x] - Dist[d*(n/(b*(m + 1))), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 52

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + n + 1))), x] + Dist[n*((b*c - a*d)/(b*(m + n + 1))), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 209

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*ArcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 223

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rubi steps

\begin {align*} \int \frac {x^{5/2}}{(a-b x)^{5/2}} \, dx &=\frac {2 x^{5/2}}{3 b (a-b x)^{3/2}}-\frac {5 \int \frac {x^{3/2}}{(a-b x)^{3/2}} \, dx}{3 b}\\ &=\frac {2 x^{5/2}}{3 b (a-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a-b x}}+\frac {5 \int \frac {\sqrt {x}}{\sqrt {a-b x}} \, dx}{b^2}\\ &=\frac {2 x^{5/2}}{3 b (a-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a-b x}}-\frac {5 \sqrt {x} \sqrt {a-b x}}{b^3}+\frac {(5 a) \int \frac {1}{\sqrt {x} \sqrt {a-b x}} \, dx}{2 b^3}\\ &=\frac {2 x^{5/2}}{3 b (a-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a-b x}}-\frac {5 \sqrt {x} \sqrt {a-b x}}{b^3}+\frac {(5 a) \text {Subst}\left (\int \frac {1}{\sqrt {a-b x^2}} \, dx,x,\sqrt {x}\right )}{b^3}\\ &=\frac {2 x^{5/2}}{3 b (a-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a-b x}}-\frac {5 \sqrt {x} \sqrt {a-b x}}{b^3}+\frac {(5 a) \text {Subst}\left (\int \frac {1}{1+b x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt {a-b x}}\right )}{b^3}\\ &=\frac {2 x^{5/2}}{3 b (a-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a-b x}}-\frac {5 \sqrt {x} \sqrt {a-b x}}{b^3}+\frac {5 a \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a-b x}}\right )}{b^{7/2}}\\ \end {align*}

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Mathematica [A]
time = 0.16, size = 78, normalized size = 0.82 \begin {gather*} -\frac {\sqrt {x} \left (15 a^2-20 a b x+3 b^2 x^2\right )}{3 b^3 (a-b x)^{3/2}}+\frac {5 a \log \left (-\sqrt {-b} \sqrt {x}+\sqrt {a-b x}\right )}{(-b)^{7/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^(5/2)/(a - b*x)^(5/2),x]

[Out]

-1/3*(Sqrt[x]*(15*a^2 - 20*a*b*x + 3*b^2*x^2))/(b^3*(a - b*x)^(3/2)) + (5*a*Log[-(Sqrt[-b]*Sqrt[x]) + Sqrt[a -
b*x]])/(-b)^(7/2)

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Mathics [C] Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
time = 11.14, size = 523, normalized size = 5.51 \begin {gather*} \text {Piecewise}\left [\left \{\left \{\frac {15 a^{\frac {7}{2}} b^{\frac {17}{2}} \left (\text {Pi}-2 I \text {ArcCosh}\left [\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right ]\right ) \left (\frac {-a+b x}{a}\right )^{\frac {3}{2}} \left (a-b x\right )^4+30 I a^2 b^9 \sqrt {x} \left (-a+b x\right )^5+15 a^{\frac {5}{2}} b^{\frac {19}{2}} x \left (-\text {Pi}+2 I \text {ArcCosh}\left [\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right ]\right ) \left (\frac {-a+b x}{a}\right )^{\frac {3}{2}} \left (a-b x\right )^4-40 I a b^{10} x^{\frac {3}{2}} \left (-a+b x\right )^5+6 I b^{11} x^{\frac {5}{2}} \left (-a+b x\right )^5}{6 a^{\frac {3}{2}} b^{12} \left (\frac {-a+b x}{a}\right )^{\frac {3}{2}} \left (a-b x\right )^5},\text {Abs}\left [\frac {b x}{a}\right ]>1\right \}\right \},\frac {15 a^{\frac {81}{2}} b^{22} x^{\frac {51}{2}} \text {ArcSin}\left [\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right ] \sqrt {1-\frac {b x}{a}}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1-\frac {b x}{a}}-3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1-\frac {b x}{a}}}-\frac {15 a^{40} b^{\frac {45}{2}} x^{26}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1-\frac {b x}{a}}-3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1-\frac {b x}{a}}}-\frac {15 a^{\frac {79}{2}} b^{23} x^{\frac {53}{2}} \text {ArcSin}\left [\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right ] \sqrt {1-\frac {b x}{a}}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1-\frac {b x}{a}}-3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1-\frac {b x}{a}}}+\frac {20 a^{39} b^{\frac {47}{2}} x^{27}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1-\frac {b x}{a}}-3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1-\frac {b x}{a}}}-\frac {3 a^{38} b^{\frac {49}{2}} x^{28}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1-\frac {b x}{a}}-3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1-\frac {b x}{a}}}\right ] \end {gather*}

Warning: Unable to verify antiderivative.

[In]

mathics('Integrate[x^(5/2)/(a - b*x)^(5/2),x]')

[Out]

Piecewise[{{(15 a ^ (7 / 2) b ^ (17 / 2) (Pi - 2 I ArcCosh[Sqrt[b] Sqrt[x] / Sqrt[a]]) ((-a + b x) / a) ^ (3 /
2) (a - b x) ^ 4 + 30 I a ^ 2 b ^ 9 Sqrt[x] (-a + b x) ^ 5 + 15 a ^ (5 / 2) b ^ (19 / 2) x (-Pi + 2 I ArcCosh
[Sqrt[b] Sqrt[x] / Sqrt[a]]) ((-a + b x) / a) ^ (3 / 2) (a - b x) ^ 4 - 40 I a b ^ 10 x ^ (3 / 2) (-a + b x) ^
5 + 6 I b ^ 11 x ^ (5 / 2) (-a + b x) ^ 5) / (6 a ^ (3 / 2) b ^ 12 ((-a + b x) / a) ^ (3 / 2) (a - b x) ^ 5),
Abs[b x / a] > 1}}, 15 a ^ (81 / 2) b ^ 22 x ^ (51 / 2) ArcSin[Sqrt[b] Sqrt[x] / Sqrt[a]] Sqrt[1 - b x / a] /
(3 a ^ (79 / 2) b ^ (51 / 2) x ^ (51 / 2) Sqrt[1 - b x / a] - 3 a ^ (77 / 2) b ^ (53 / 2) x ^ (53 / 2) Sqrt[1
- b x / a]) - 15 a ^ 40 b ^ (45 / 2) x ^ 26 / (3 a ^ (79 / 2) b ^ (51 / 2) x ^ (51 / 2) Sqrt[1 - b x / a] - 3
a ^ (77 / 2) b ^ (53 / 2) x ^ (53 / 2) Sqrt[1 - b x / a]) - 15 a ^ (79 / 2) b ^ 23 x ^ (53 / 2) ArcSin[Sqrt[b
] Sqrt[x] / Sqrt[a]] Sqrt[1 - b x / a] / (3 a ^ (79 / 2) b ^ (51 / 2) x ^ (51 / 2) Sqrt[1 - b x / a] - 3 a ^ (
77 / 2) b ^ (53 / 2) x ^ (53 / 2) Sqrt[1 - b x / a]) + 20 a ^ 39 b ^ (47 / 2) x ^ 27 / (3 a ^ (79 / 2) b ^ (51
/ 2) x ^ (51 / 2) Sqrt[1 - b x / a] - 3 a ^ (77 / 2) b ^ (53 / 2) x ^ (53 / 2) Sqrt[1 - b x / a]) - 3 a ^ 38
b ^ (49 / 2) x ^ 28 / (3 a ^ (79 / 2) b ^ (51 / 2) x ^ (51 / 2) Sqrt[1 - b x / a] - 3 a ^ (77 / 2) b ^ (53 / 2
) x ^ (53 / 2) Sqrt[1 - b x / a])]

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(159\) vs. \(2(71)=142\).
time = 0.12, size = 160, normalized size = 1.68

method	result	size
risch	\(-\frac {\sqrt {x}\, \sqrt {-b x +a}}{b^{3}}+\frac {\left (\frac {5 a \arctan \left (\frac {\sqrt {b}\, \left (x -\frac {a}{2 b}\right )}{\sqrt {-x^{2} b +a x}}\right )}{2 b^{\frac {7}{2}}}+\frac {2 a^{2} \sqrt {-\left (-\frac {a}{b}+x \right )^{2} b -a \left (-\frac {a}{b}+x \right )}}{3 b^{5} \left (-\frac {a}{b}+x \right )^{2}}+\frac {14 a \sqrt {-\left (-\frac {a}{b}+x \right )^{2} b -a \left (-\frac {a}{b}+x \right )}}{3 b^{4} \left (-\frac {a}{b}+x \right )}\right ) \sqrt {x \left (-b x +a \right )}}{\sqrt {x}\, \sqrt {-b x +a}}\)	\(160\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(5/2)/(-b*x+a)^(5/2),x,method=_RETURNVERBOSE)

[Out]

-x^(1/2)*(-b*x+a)^(1/2)/b^3+(5/2/b^(7/2)*a*arctan(b^(1/2)*(x-1/2*a/b)/(-b*x^2+a*x)^(1/2))+2/3/b^5*a^2/(-a/b+x)
^2*(-(-a/b+x)^2*b-a*(-a/b+x))^(1/2)+14/3/b^4*a/(-a/b+x)*(-(-a/b+x)^2*b-a*(-a/b+x))^(1/2))*(x*(-b*x+a))^(1/2)/x
^(1/2)/(-b*x+a)^(1/2)

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Maxima [A]
time = 0.34, size = 94, normalized size = 0.99 \begin {gather*} \frac {2 \, a b^{2} + \frac {10 \, {\left (b x - a\right )} a b}{x} - \frac {15 \, {\left (b x - a\right )}^{2} a}{x^{2}}}{3 \, {\left (\frac {{\left (-b x + a\right )}^{\frac {3}{2}} b^{4}}{x^{\frac {3}{2}}} + \frac {{\left (-b x + a\right )}^{\frac {5}{2}} b^{3}}{x^{\frac {5}{2}}}\right )}} - \frac {5 \, a \arctan \left (\frac {\sqrt {-b x + a}}{\sqrt {b} \sqrt {x}}\right )}{b^{\frac {7}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)/(-b*x+a)^(5/2),x, algorithm="maxima")

[Out]

1/3*(2*a*b^2 + 10*(b*x - a)*a*b/x - 15*(b*x - a)^2*a/x^2)/((-b*x + a)^(3/2)*b^4/x^(3/2) + (-b*x + a)^(5/2)*b^3
/x^(5/2)) - 5*a*arctan(sqrt(-b*x + a)/(sqrt(b)*sqrt(x)))/b^(7/2)

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Fricas [A]
time = 0.33, size = 215, normalized size = 2.26 \begin {gather*} \left [-\frac {15 \, {\left (a b^{2} x^{2} - 2 \, a^{2} b x + a^{3}\right )} \sqrt {-b} \log \left (-2 \, b x + 2 \, \sqrt {-b x + a} \sqrt {-b} \sqrt {x} + a\right ) + 2 \, {\left (3 \, b^{3} x^{2} - 20 \, a b^{2} x + 15 \, a^{2} b\right )} \sqrt {-b x + a} \sqrt {x}}{6 \, {\left (b^{6} x^{2} - 2 \, a b^{5} x + a^{2} b^{4}\right )}}, -\frac {15 \, {\left (a b^{2} x^{2} - 2 \, a^{2} b x + a^{3}\right )} \sqrt {b} \arctan \left (\frac {\sqrt {-b x + a}}{\sqrt {b} \sqrt {x}}\right ) + {\left (3 \, b^{3} x^{2} - 20 \, a b^{2} x + 15 \, a^{2} b\right )} \sqrt {-b x + a} \sqrt {x}}{3 \, {\left (b^{6} x^{2} - 2 \, a b^{5} x + a^{2} b^{4}\right )}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)/(-b*x+a)^(5/2),x, algorithm="fricas")

[Out]

[-1/6*(15*(a*b^2*x^2 - 2*a^2*b*x + a^3)*sqrt(-b)*log(-2*b*x + 2*sqrt(-b*x + a)*sqrt(-b)*sqrt(x) + a) + 2*(3*b^
3*x^2 - 20*a*b^2*x + 15*a^2*b)*sqrt(-b*x + a)*sqrt(x))/(b^6*x^2 - 2*a*b^5*x + a^2*b^4), -1/3*(15*(a*b^2*x^2 -
2*a^2*b*x + a^3)*sqrt(b)*arctan(sqrt(-b*x + a)/(sqrt(b)*sqrt(x))) + (3*b^3*x^2 - 20*a*b^2*x + 15*a^2*b)*sqrt(-
b*x + a)*sqrt(x))/(b^6*x^2 - 2*a*b^5*x + a^2*b^4)]

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Sympy [C] Result contains complex when optimal does not.
time = 5.43, size = 971, normalized size = 10.22

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(5/2)/(-b*x+a)**(5/2),x)

[Out]

Piecewise((-30*I*a**(81/2)*b**22*x**(51/2)*sqrt(-1 + b*x/a)*acosh(sqrt(b)*sqrt(x)/sqrt(a))/(6*a**(79/2)*b**(51
/2)*x**(51/2)*sqrt(-1 + b*x/a) - 6*a**(77/2)*b**(53/2)*x**(53/2)*sqrt(-1 + b*x/a)) + 15*pi*a**(81/2)*b**22*x**
(51/2)*sqrt(-1 + b*x/a)/(6*a**(79/2)*b**(51/2)*x**(51/2)*sqrt(-1 + b*x/a) - 6*a**(77/2)*b**(53/2)*x**(53/2)*sq
rt(-1 + b*x/a)) + 30*I*a**(79/2)*b**23*x**(53/2)*sqrt(-1 + b*x/a)*acosh(sqrt(b)*sqrt(x)/sqrt(a))/(6*a**(79/2)*
b**(51/2)*x**(51/2)*sqrt(-1 + b*x/a) - 6*a**(77/2)*b**(53/2)*x**(53/2)*sqrt(-1 + b*x/a)) - 15*pi*a**(79/2)*b**
23*x**(53/2)*sqrt(-1 + b*x/a)/(6*a**(79/2)*b**(51/2)*x**(51/2)*sqrt(-1 + b*x/a) - 6*a**(77/2)*b**(53/2)*x**(53
/2)*sqrt(-1 + b*x/a)) + 30*I*a**40*b**(45/2)*x**26/(6*a**(79/2)*b**(51/2)*x**(51/2)*sqrt(-1 + b*x/a) - 6*a**(7
7/2)*b**(53/2)*x**(53/2)*sqrt(-1 + b*x/a)) - 40*I*a**39*b**(47/2)*x**27/(6*a**(79/2)*b**(51/2)*x**(51/2)*sqrt(
-1 + b*x/a) - 6*a**(77/2)*b**(53/2)*x**(53/2)*sqrt(-1 + b*x/a)) + 6*I*a**38*b**(49/2)*x**28/(6*a**(79/2)*b**(5
1/2)*x**(51/2)*sqrt(-1 + b*x/a) - 6*a**(77/2)*b**(53/2)*x**(53/2)*sqrt(-1 + b*x/a)), Abs(b*x/a) > 1), (15*a**(
81/2)*b**22*x**(51/2)*sqrt(1 - b*x/a)*asin(sqrt(b)*sqrt(x)/sqrt(a))/(3*a**(79/2)*b**(51/2)*x**(51/2)*sqrt(1 -
b*x/a) - 3*a**(77/2)*b**(53/2)*x**(53/2)*sqrt(1 - b*x/a)) - 15*a**(79/2)*b**23*x**(53/2)*sqrt(1 - b*x/a)*asin(
sqrt(b)*sqrt(x)/sqrt(a))/(3*a**(79/2)*b**(51/2)*x**(51/2)*sqrt(1 - b*x/a) - 3*a**(77/2)*b**(53/2)*x**(53/2)*sq
rt(1 - b*x/a)) - 15*a**40*b**(45/2)*x**26/(3*a**(79/2)*b**(51/2)*x**(51/2)*sqrt(1 - b*x/a) - 3*a**(77/2)*b**(5
3/2)*x**(53/2)*sqrt(1 - b*x/a)) + 20*a**39*b**(47/2)*x**27/(3*a**(79/2)*b**(51/2)*x**(51/2)*sqrt(1 - b*x/a) -
3*a**(77/2)*b**(53/2)*x**(53/2)*sqrt(1 - b*x/a)) - 3*a**38*b**(49/2)*x**28/(3*a**(79/2)*b**(51/2)*x**(51/2)*sq
rt(1 - b*x/a) - 3*a**(77/2)*b**(53/2)*x**(53/2)*sqrt(1 - b*x/a)), True))

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Giac [A]
time = 0.01, size = 146, normalized size = 1.54 \begin {gather*} 2 \left (\frac {2 \left (\left (-\frac {\frac {1}{36}\cdot 9 b^{4} a \sqrt {x} \sqrt {x}}{b^{5} a}+\frac {\frac {1}{36}\cdot 60 b^{3} a^{2}}{b^{5} a}\right ) \sqrt {x} \sqrt {x}-\frac {\frac {1}{36}\cdot 45 b^{2} a^{3}}{b^{5} a}\right ) \sqrt {x} \sqrt {a-b x}}{\left (a-b x\right )^{2}}-\frac {10 a \ln \left |\sqrt {a-b x}-\sqrt {-b} \sqrt {x}\right |}{4 b^{3} \sqrt {-b}}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(5/2)/(-b*x+a)^(5/2),x)

[Out]

-1/3*sqrt(-b*x + a)*(x*(3*x/b - 20*a/b^2) + 15*a^2/b^3)*sqrt(x)/(b*x - a)^2 - 5*a*log(abs(-sqrt(-b)*sqrt(x) +
sqrt(-b*x + a)))/(sqrt(-b)*b^3)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^{5/2}}{{\left (a-b\,x\right )}^{5/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(5/2)/(a - b*x)^(5/2),x)

[Out]

int(x^(5/2)/(a - b*x)^(5/2), x)

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